10v^2-13v-30=0

Solution for 10v^2-13v-30=0 equation:

10v^2-13v-30=0

a = 10; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·10·(-30)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-37}{2*10}=\frac{-24}{20}
=-1+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+37}{2*10}=\frac{50}{20}
=2+1/2
$